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Topic · Straight Lines

Straight lines: slope from general form, and signs from a sketch

The two operations in 'negative reciprocal' and why doing one of them is the commonest slip, how to read coefficient signs off a sketch without assuming they are positive, and where the minus sign in the slope comes from.

6 min readUpdated 5 September 2026

A straight line arrives in Paper 2 in one of two disguises. Either you are given its equation and asked for a geometric fact — slope, intercept, a perpendicular — or you are shown a sketch and asked what its equation's coefficients must satisfy. The first is mechanical once you have the right formula. The second is where the marks go.

Misconception 1: slope from the general form

Written as ax+by+c=0ax + by + c = 0, the line's slope is

m=−ab,m = -\frac{a}{b},

not a/ba/b and not −b/a-b/a. The minus sign is not a convention to memorise; it falls straight out of rearranging into y=mx+dy = mx + d:

by=−ax−c  ⟹  y=−abx−cb.by = -ax - c \;\Longrightarrow\; y = -\frac{a}{b}x - \frac{c}{b}.

The same rearrangement hands you the yy-intercept, −c/b-c/b, which is the other value people quote with the wrong sign. If you ever doubt either, spend the four seconds rearranging rather than recalling.

Misconception 2: half of "negative reciprocal"

Two perpendicular lines have slopes whose product is −1-1, so the perpendicular slope is the negative reciprocal:

m⊥=−1m.m_{\perp} = -\frac{1}{m}.

That is two operations — flip, then negate. Applying one of them is the single commonest error in the topic, and it is invisible in the working because each half is a legitimate-looking manipulation. A slope of 23\tfrac{2}{3} has perpendicular slope −32-\tfrac{3}{2}; the two near misses, 32\tfrac{3}{2} and −23-\tfrac{2}{3}, are exactly the numbers a well-built option list will contain.

The check costs nothing: multiply your two slopes. If the product is not −1-1, you did one operation.

Misconception 3: assuming the coefficients are positive

Given a sketch and the equation ax+by+c=0ax + by + c = 0, the question is usually which of aa, bb, cc are positive. The error is to reason as though b>0b \gt 0 and read everything else off that assumption — which is right exactly half the time and gives no signal when it is not.

Reason from the two things a sketch really tells you, the sign of the slope and the sign of the yy-intercept, and translate each into a statement about a ratio:

Ratios are all a sketch can determine. Any question that has a unique answer must have pinned one coefficient's sign some other way — find where it did that before choosing.

A worked example

Consider the line 2x−3y+6=02x - 3y + 6 = 0.

Rearranging: 3y=2x+63y = 2x + 6, so y=23x+2y = \tfrac{2}{3}x + 2. The slope is 23\tfrac{2}{3} and the yy-intercept is 22.

Reading the slope straight off the coefficients as 2−3\tfrac{2}{-3} gives −23-\tfrac{2}{3} — the right magnitude, the wrong sign, and a line sloping the wrong way. Reading it as −32-\tfrac{3}{2} inverts it as well.

Now the perpendicular through the same intercept:

m⊥=−12/3=−32,y=−32x+2.m_{\perp} = -\frac{1}{2/3} = -\frac{3}{2}, \qquad y = -\tfrac{3}{2}x + 2.

Check: 23×(−32)=−1\tfrac{2}{3} \times \left(-\tfrac{3}{2}\right) = -1. Had we written 32\tfrac{3}{2}, the product would have been 11 and the error would have announced itself in one multiplication.

Check yourself

Rearrange, don't recall — four seconds of algebra beats a half-remembered sign. And after every perpendicular slope, multiply the two slopes and confirm you get −1-1.

The drill below generates new coefficients each time, including negative ones, so the "assume positive" shortcut cannot survive.

Now do some

A drill session on Straight Lines — fresh questions each time, generated from the same syllabus objectives this guide explains, and machine-checked twice before you see them.

Original study notes by Dsetopia, written from the EDB syllabus learning objectives. Not affiliated with the HKEAA; no exam content is reproduced.