This topic is about figures that have the same shape. You need the conditions for two triangles to be congruent or similar, and how lengths, areas and volumes scale between similar figures — most often a triangle cut by a line parallel to one side.
What this topic covers
Conditions for congruent and similar triangles
Ratios of corresponding sides in similar figures
Areas scale by the square of the length ratio, volumes by the cube
In the figure, DD and FF are points on ABAB, and EE and GG are points on ACAC, such that DE∥FG∥BCDE FG BC. It is given that AD:DF:FB=3:4:1AD : DF : FB equals 3 : 4 : 1 and the area of △AFGAFG is 392 cm2392 cm squared. The area of the trapezium DBCEDBCE is
A320 cm2.320 cm squared .
B440 cm2.440 cm squared .
C448 cm2.448 cm squared .
D512 cm2.512 cm squared .
Show the answer and solution
Answer: B
Worked solution
AD:AF:AB=3:7:8△ADE∼△AFG∼△ABC, so their areas are as 32:72:82△ABC=392×4964=512 cm2△ADE=392×499=72 cm2DBCE=512−72=440 cm2
Sample 2
In the figure, ∠BAC=90∘angle BAC equals 90 degrees and AD⊥BCAD BC, where DD lies on BCBC. If AC=65AC equals 65 cm and DC=25DC equals 25 cm, then BD=BD equals
A85 cm.85 cm .
B144 cm.144 cm .
C156 cm.156 cm .
D169 cm.169 cm .
Show the answer and solution
Answer: B
Worked solution
△ACD∼△BCA (equiangular)AC2=DC×BC⇒BC=25652=169 cmBD=BC−DC=169−25=144 cm
Try a whole paper
The free mock is a full 45-question Paper 2 under exam timing, marked the moment you submit, with a report by topic.